document.write( "Question 1087657: My Question: If THREE cards are dealt from a 52 card deck, what is the probability that at least one of those cards will be an Ace, Jack, or Seven?\r
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document.write( "My Thoughts: There are 4 Aces, 4 Jacks, and 4 Sevens in a 52 card deck. If you are dealt one card, you have a 12/52 or 23.1% chance that the card dealt is an Ace, Jack, or Seven. But I have no idea what the next step is when figuring out the probability if 3 cards are dealt. If I did 12/52+12/51+12/50, then the answer would be 70.6% which seems too high. PLEASE HELP! \n" );
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Algebra.Com's Answer #701956 by math_helper(2461)![]() ![]() You can put this solution on YOUR website! A = { A, J, or 7 drawn } \n" ); document.write( "B = { all the other cards }\r \n" ); document.write( "\n" ); document.write( "So yes, there are 12 cards of interest. That means there are 40 other cards. \r \n" ); document.write( "\n" ); document.write( "Pr(A) = 1 - Pr(only cards from B are drawn) \n" ); document.write( " = 1 - (40/52)*(39/51)*(38/50) \n" ); document.write( " = 1 - (38/(17*5)) \n" ); document.write( " ~= \n" ); document.write( "\n" ); document.write( "( ~= used to indicate approximation) \n" ); document.write( " |