document.write( "Question 96260: Maria and Eduardo are traveling to a business conference. The trip takes 2 hr for Maria and 2.5 hr for Eduardo, since he lives 40 mi farther away. Eduardo travels 5 mph faster than Maria. Find their average rates. \n" ); document.write( "
Algebra.Com's Answer #70195 by ankor@dixie-net.com(22740)\"\" \"About 
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Maria and Eduardo are traveling to a business conference. The trip takes 2 hr for Maria and 2.5 hr for Eduardo, since he lives 40 mi farther away. Eduardo travels 5 mph faster than Maria. Find their average rates.
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\n" ); document.write( "Let s = M's speed
\n" ); document.write( "Then
\n" ); document.write( "(s+5) = E's speed
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\n" ); document.write( "Write a distance equation: Dist = Time * speed
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\n" ); document.write( "E's trip - M's trip = 40
\n" ); document.write( "2.5(s+5) - 2s = 40
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\n" ); document.write( "2.5s + 12.5 - 2s = 40
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\n" ); document.write( "2.5s - 2s = 40 - 12.5
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\n" ); document.write( ".5s = 27.5
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\n" ); document.write( "s = 27.5/.5
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\n" ); document.write( "s = 55 mph is M's speed
\n" ); document.write( "then
\n" ); document.write( "55 + 5 = 60 mph is E's speed
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\n" ); document.write( "Check our solutions by finding the distances
\n" ); document.write( "M: 2 * 55 = 110 mi
\n" ); document.write( "E: 2.5 * 60 = 150 mi which is 40 mi further
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\n" ); document.write( "Did the make sense to you. Not that hard, right?\r
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