document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1087657>Question 1087657</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My Question: If THREE cards are dealt from a 52 card deck, what is the probability that at least one of those cards will be an Ace, Jack, or Seven?\r<BR>\n" );
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document.write( "My Thoughts: There are 4 Aces, 4 Jacks, and 4 Sevens in a 52 card deck. If you are dealt one card, you have a 12/52 or 23.1% chance that the card dealt is an Ace, Jack, or Seven. But I have no idea what the next step is when figuring out the probability if 3 cards are dealt. If I did 12/52+12/51+12/50, then the answer would be 70.6% which seems too high. PLEASE HELP! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #701948 by </B><A HREF=/tutors/aboutme.mpl?userid=natolino_2017><B>natolino_2017(77)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=natolino_2017><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=701948\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In this case we can use Hypergeometric Distribution with N=52 (total number of cards), n= 3 (number of dealt cards), d = 4 + 4 + 4 = 12 (total working cards)\r<BR>\n" );
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document.write( "P(X=x) = (dCx)* ((N-d)C(n-x))/(NCn).\r<BR>\n" );
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document.write( "P(X>=1) = 1 - P(x=0) (using the complement rule).\r<BR>\n" );
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document.write( "Using the general term with x=0, P(x=0) = (12C0)(40C3)/(52C3) = 38/85.\r<BR>\n" );
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document.write( "So the answer is 1 - 38/85 = 47/85 =0,553\r<BR>\n" );
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document.write( "@natolino_    </SPAN>\n" );
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