document.write( "Question 1087582: In triangle ABC, angle ABC = 90º, and point D lies on segment BC such that AD is an angle bisector. If AB = 12 and BD = 4, then find AC
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Algebra.Com's Answer #701938 by Edwin McCravy(20055)\"\" \"About 
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document.write( "\"tan%28%22%3CBAD%22%29\"\"%22%22=%22%22\"\"BD%2F%28AB%29\"\"%22%22=%22%22\"\"4%2F12\"\"%22%22=%22%22\"\"1%2F3\"\r\n" );
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document.write( "Since AD is the angle bisector of ∠BAC, ∠BAC = 2∠BAD.\r\n" );
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document.write( "Use formula \"tan%282%2Atheta%29\"\"%22%22=%22%22\"\"2tan%5E%22%22%28theta%29%2F%281-tan%5E2%28theta%29%29\"\r\n" );
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document.write( "\"tan%28%22%3CBAC%22%29\"\"%22%22=%22%22\"\"tan%282%2A%22%3CBAD%22%29\"\"%22%22=%22%22\"\"2tan%5E%22%22%28%22%3CBAD%22%29%2F%281-tan%5E2%28%22%3CBAD%22%29%29\"\"%22%22=%22%22\"\"2%281%2F3%29%2F%281%2B%281%2F3%29%5E2%29\"\"%22%22=%22%22\"\"%282%2F3%29%2F%281-1%2F9%29\"\"%22%22=%22%22\"\"%282%2F3%29%2F%288%2F9%29\"\"%22%22=%22%22\"\"%282%2F3%29%289%2F8%29\"\"%22%22=%22%22\"\"18%2F24\"\"%22%22=%22%22\"\"3%2F4\"\r\n" );
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document.write( "And since also \"tan%28%22%3CBAC%22%29\"\"%22%22=%22%22\"\"OPPOSITE%2FADJACENT=BC%2F%28AB%29\"\"%22%22=%22%22\"\"BC%2F12\"\r\n" );
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document.write( "\"BC%2F12\"\"%22%22=%22%22\"\"3%2F4\"\r\n" );
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document.write( "\"4%2ABC\"\"%22%22=%22%22\"\"36\"\r\n" );
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document.write( "\"BC\"\"%22%22=%22%22\"\"9\", (which means, incidentally that DC = 5)\r\n" );
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document.write( "By the Pythagorean theorem:\r\n" );
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document.write( "\"AC%5E2\"\"%22%22=%22%22\"\"AB%5E2%2BBC%5E2\"\r\n" );
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document.write( "\"AC%5E2\"\"%22%22=%22%22\"\"12%5E2%2B9%5E2\"\r\n" );
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document.write( "\"AC%5E2\"\"%22%22=%22%22\"\"144%2B81\"\r\n" );
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document.write( "\"AC%5E2\"\"%22%22=%22%22\"\"225\"\r\n" );
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document.write( "\"AC\"\"%22%22=%22%22\"\"sqrt%28225%29\"\r\n" );
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document.write( "\"AC\"\"%22%22=%22%22\"\"15\"\r\n" );
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document.write( "Edwin
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