document.write( "Question 96432: HELP!!! OK I tried to do this but it didn't work...\r
\n" ); document.write( "\n" ); document.write( "Problem: The length of a rectangle is 3 meters less than twice the width. The perimeter is 18 meters. Find the width.\r
\n" ); document.write( "\n" ); document.write( "So is it 18=2*2x-3*2x\r
\n" ); document.write( "\n" ); document.write( "THANK YOU SO MUCH AGAIN!\r
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Algebra.Com's Answer #70192 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
L=2W-3
\n" ); document.write( "2(2W-3)+2W=18
\n" ); document.write( "4W-6+2W=18
\n" ); document.write( "6W=18+6
\n" ); document.write( "6W=24
\n" ); document.write( "W=24/6
\n" ); document.write( "W=4 FOR THE WIDTH.
\n" ); document.write( "L=2*4-3
\n" ); document.write( "L=8-3
\n" ); document.write( "L=5 FOR THE LENGTH.
\n" ); document.write( "PROOF
\n" ); document.write( "2*5+2*4=18
\n" ); document.write( "10+8=18
\n" ); document.write( "18=18
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