document.write( "Question 1087595: 1) What is the measure of an angle if it is 360 less than five times its own supplement? \r
\n" ); document.write( "\n" ); document.write( "2) What is the measure of an angle if it is 190 less than six times its own complement?
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Algebra.Com's Answer #701915 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "1) What is the measure of an angle if it is \"360\" less than five times its own supplement? \r
\n" ); document.write( "\n" ); document.write( "Two angles are supplementary when they add up to \"180\" degrees.\r
\n" ); document.write( "\n" ); document.write( "if angle is \"x\", its supplement is \"180-x\"\r
\n" ); document.write( "\n" ); document.write( "if the measure of an angle if it is \"360\" less than \"five\"\"+times\" its own supplement, we have\r
\n" ); document.write( "\n" ); document.write( "\"x%2B360=5%28180-x%29\"....solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B360=900-5x\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B5x=900-360\"\r
\n" ); document.write( "\n" ); document.write( "\"6x=540\"\r
\n" ); document.write( "\n" ); document.write( "\"x=540%2F6\"\r
\n" ); document.write( "\n" ); document.write( "\"x=90\"-> the angle\r
\n" ); document.write( "\n" ); document.write( "\"180-x=180-90=90\"->its supplement\r
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\n" ); document.write( "\n" ); document.write( "2) What is the measure of an angle if it is \"190\" less than \"six\"\"+times\" its own complement? \r
\n" ); document.write( "\n" ); document.write( "Two angles are complementary when they add up to \"90\" degrees.\r
\n" ); document.write( "\n" ); document.write( "if angle is \"x\", its complement is \"90-x\"\r
\n" ); document.write( "\n" ); document.write( "if the measure of an angle if it is \"190\" less than \"six\"\"+times\" its own complement, we have\r
\n" ); document.write( "\n" ); document.write( "\"x%2B190=6%2890-x%29\"....solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B190=540-6x\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B6x=540-190\"\r
\n" ); document.write( "\n" ); document.write( "\"7x=350\"\r
\n" ); document.write( "\n" ); document.write( "\"x=350%2F7\"\r
\n" ); document.write( "\n" ); document.write( "\"x=50\"-> the angle\r
\n" ); document.write( "\n" ); document.write( "\"90-x=90-50=40\" ->its complement\r
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