document.write( "Question 1087535: The size P of a certain insect population at time t (in days) obeys the function p(t)=700e^0.05t\r
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document.write( "a)Determine the number of insects at t=0 days.\r
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document.write( "b)What is the growth rate of the insect population?\r
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document.write( "c)What is the population after 10 days?\r
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document.write( "d)When will the insect population reach 1050?\r
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document.write( "e)When will the insect population double? \n" );
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Algebra.Com's Answer #701859 by mathmate(429)![]() ![]() You can put this solution on YOUR website! Question: \n" ); document.write( "The size P of a certain insect population at time t (in days) obeys the function p(t)=700e^0.05t \n" ); document.write( "a)Determine the number of insects at t=0 days. \n" ); document.write( "b)What is the growth rate of the insect population? \n" ); document.write( "c)What is the population after 10 days? \n" ); document.write( "d)When will the insect population reach 1050? \n" ); document.write( "e)When will the insect population double? \n" ); document.write( " \n" ); document.write( "Solution: \n" ); document.write( "Given : P(t)=700e^(0.5t), t in days \n" ); document.write( " \n" ); document.write( "(a) number of insects at t=0 days \n" ); document.write( "number of insects = P(0)=700(1)=700. \n" ); document.write( " \n" ); document.write( "(b) the growth rate is the percentage increase between days \n" ); document.write( "=P(t+1)/P(t)=700e^(0.5(t+1))/700e^(0.5t)=e^(0.5(1))=e^0.5=1.64872 \n" ); document.write( "therefore the growth rate is 64.872% per day. \n" ); document.write( " \n" ); document.write( "(c) population after 10 days \n" ); document.write( "P(10)=700e^(0.5*10)=700(148.41)=103889 \n" ); document.write( " \n" ); document.write( "(d) the population will reach 1050 when P(t)=1050, or \n" ); document.write( "700e^0.5t=1050 => \n" ); document.write( "e^(0.5t)=1050/700=1.5 \n" ); document.write( "take log \n" ); document.write( "0.5t=log(3/2) => \n" ); document.write( "t=2log(3/2)=0.8109 days \n" ); document.write( "=approximately 19.5 hours \n" ); document.write( " \n" ); document.write( "(e) population will double when P(t)=2*700=1400 \n" ); document.write( "700e^(0.5t)=1400 => \n" ); document.write( "e^(0.5t)=1400/700=2 \n" ); document.write( "take log \n" ); document.write( "0.5t=log(2) \n" ); document.write( "t=2log(2)=1.3863 \n" ); document.write( "=33.27 hours. \n" ); document.write( " \n" ); document.write( "Note: log(x) is log to the base e, or natural log. Log10 is mostly used in high-school. \n" ); document.write( " |