document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1087537>Question 1087537</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the amount that results from the given investment.\r<BR>\n" );
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document.write( "$200.00 invested at 10% compounded quarterly after a period of 3 1/2 years \r<BR>\n" );
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document.write( "After 31/2 years, the investment results in $?<BR>\n" );
document.write( "(Round to the nearest cent as needed) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #701851 by </B><A HREF=/tutors/aboutme.mpl?userid=mathmate><B>mathmate(429)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathmate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mathmate><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=701851\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Question:<BR>\n" );
document.write( "Find the amount that results from the given investment.<BR>\n" );
document.write( "$200.00 invested at 10% compounded quarterly after a period of 3 1/2 years <BR>\n" );
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document.write( "Solution:<BR>\n" );
document.write( "Principal, P=$200<BR>\n" );
document.write( "APR=10%<BR>\n" );
document.write( "interest per period (quarter), i=0.10/4=0.025<BR>\n" );
document.write( "number of periods, n=3.5*4=14<BR>\n" );
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document.write( "Future value (accumulated amount)<BR>\n" );
document.write( "=P(1+i)^n<BR>\n" );
document.write( "=200*(1+0.025)^14<BR>\n" );
document.write( "=200*(1.41297)<BR>\n" );
document.write( "=$282.59 </SPAN>\n" );
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