document.write( "Question 1087514: An arrow is shot vertically with an initial speed of 25m/sec can be approximated by the function h(t)=-5t^2+25t where h(t) is the height of the arrow (in meters) and t is the time after release of the arrow (in seconds)
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document.write( "a) how high is the arrow after 2.5 secs?
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document.write( "b) how long does it take the arrow to return to the ground \n" );
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Algebra.Com's Answer #701817 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "An arrow is shot vertically with an initial speed of 25m/sec can be approximated by the function h(t)=-5t^2+25t \n" ); document.write( "where h(t) is the height of the arrow (in meters) and t is the time after release of the arrow (in seconds) \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "a) how high is the arrow after 2.5 secs? - substitute t= 2.5 into h(t) and calculate.\r\n" ); document.write( "\r\n" ); document.write( "b) how long does it take the arrow to return to the ground - Find the positive root of the quadratic equation h(t) = 0.\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |