document.write( "Question 1087484: A reporter bought hamburgers at randomly selected stores of two different restaurant chains, and had the number of Calories in each hamburger measured. Can the reporter conclude, at alpha = 0.05, that the hamburgers from the two chains have a different number of Calories??\r
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document.write( "Chain A sample size 7, sample mean 280 cal, sample standard deviation 21 cal
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document.write( "Chain B sample size 8, sample mean 315 cal, sample standard deviation 27 cal\r
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document.write( "a. No, because the test value –0.23 is inside the noncritical region\r
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document.write( "b. Yes, because the test value –0.23 is inside the noncritical region\r
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document.write( "c. Yes, because the test value –2.82 is outside the noncritical region\r
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document.write( "d. No, because the test value –1.29 is inside the noncritical region \n" );
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Algebra.Com's Answer #701797 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Null Hypothesis Using Symbols\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "H0: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Alternative Hypothesis Using Symbols\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "H1: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The symbol \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Null Hypothesis in English: The two hamburger chains have burgers with the same number of Calories\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Alternative Hypothesis in English: The two hamburger chains have burgers with a different number of Calories\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is a two tailed test. We're going to use a two sample unpaired T test to test the hypothesis. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Given Information:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For chain A we have \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For chain B we are told \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Using the info about the sample sizes and sample standard deviations, let's compute the Standard Error (SE)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "With the SE, we can find the T test statistic\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll call this variable \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The T test statistic is approximately -2.82\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The T critical values, which I'll call \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use a table or calculator to find these critical values. In my case, I used this table to find the critical values. How? By looking in the df = 13 row (df = n1+n2-2 = 7+8-2 = 15-2 = 13; see note below). Then look in the column that has \"two tails = 0.05\" to find 2.160 in the table. This means that P(-2.160 < T < 2.160) is roughly equal to 0.95 and the area of 0.05 is in the tails (0.025 in each individual tail)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Recall that alpha = 0.05 is the significance level in this case.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note: I'm assuming the population variances are equal. This makes the df value much easier to compute. If they were assumed to be unequal, then we'd have to use a nasty formula to compute the df. I checked both versions of the df and got roughly 12.855898757298 when variances were assumed to be unequal, which is close enough to 13 in my opinion. See this page for further reading. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To recap so far, we found the following\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It's clear that \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This visual shows \n" ); document.write( " ![]() \n" ); document.write( "(Image generated by GeoGebra which is free graphing software)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The decision is therefore to reject the null hypothesis (H0). So we accept the alternate hypothesis (H1).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The conclusion, translated to common english, is that the burgers do have different calorie counts between the two burger chains. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the short answer is \"yes, the reporter can conclude that the two chains have different number of calories (at alpha = 0.05 significance level)\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The final answer is choice C. \n" ); document.write( " |