document.write( "Question 1087451: Find the rectangle of perimeter l which has the maximum area \n" ); document.write( "
Algebra.Com's Answer #701745 by math_helper(2461)\"\" \"About 
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Max area is when the rectangle is a square: L=W= \"+highlight%281%2F4%29+\"
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\n" ); document.write( "\n" ); document.write( "Proof: 2L + 2W = 1 —> \"+W=%281-2L%29%2F2+\"
\n" ); document.write( " A = LW = \"+L%281-2L%29%2F2++=+%281%2F2%29%28L-2L%5E2%29+\"\r
\n" ); document.write( "\n" ); document.write( "Take derivative of A with respect to L:
\n" ); document.write( " dA/dL = \"+%281%2F2%29%281-4L%29+\"\r
\n" ); document.write( "\n" ); document.write( "Set that to 0 and solve for L, while noting that \"d%5E2A%2FdL%5E2+=+-2+\" —> Concave down so our answer will give us a MAX:
\n" ); document.write( " \"+%281%2F2%29%281-4L%29+=+0+\"
\n" ); document.write( " \"+++4L+=+1+\"
\n" ); document.write( " \"++L+=+1%2F4+\" —> \"+W+=+1%2F4+\"
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\n" ); document.write( " Since L=W we have a square.\r
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