document.write( "Question 1087384: Object A travels at a constant velocity of 2.0 m/s and object B travels in the same direction at a constant velocity of 3.0 m/s. If object B starts 1.0 min after object A, how long will it take object B to catch object A? \n" ); document.write( "
Algebra.Com's Answer #701668 by ikleyn(52776)\"\" \"About 
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\n" ); document.write( "You forgot to mention in the condition that both objects A and B started from the same point.\r
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document.write( "Then the time under the question is\r\n" );
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document.write( "t = \"%282%2A60%29%2F%283.0-2.0%29\" = \"120%2F1\" = 120 seconds = 2 minutes.\r\n" );
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document.write( "The numerator 2*60 is the distance in meters from the starting point to A at the moment when the object B starts his move \r\n" );
document.write( "    (2 minutes = 120 seconds after A started its move).\r\n" );
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document.write( "So the numerator is the \"ahead distance\" between A and B when B started catching A.\r\n" );
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document.write( "The denominator (3.0 - 2.0) = 1 m/s is the relative speed of the body B to body A.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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\n" ); document.write( "\n" ); document.write( "On catching problems see the lesson \r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems for two bodies moving in the same direction (catching up)\r
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\n" ); document.write( "\n" ); document.write( "Also, you have this free of charge online textbook in ALGEBRA-I in this site\r
\n" ); document.write( "\n" ); document.write( "    ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r
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\n" ); document.write( "\n" ); document.write( "The referred lesson is the part of this textbook under the section \"Word problems\", the topic \"Travel and Distance problems\".\r
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