document.write( "Question 1087381: log(base3)3/4 + log(base3)4/5 + log(base3)5/6 + log(base3)6/7 + log(base3)7/8 + log(base3)8/9 divided by log4/5 + log5/6 + log6/7 + log7/8 + log9/10\r
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\n" ); document.write( "\n" ); document.write( "log(base3) (3/4*4/5*5/6*6/7*7/8*8/9) divided by log (4/5*5/6*7/8*8/9*9/10)\r
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Algebra.Com's Answer #701666 by ikleyn(52799)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Next step notice that\r\n" );
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document.write( "\"3%2F4%2A4%2F5%2A5%2F6%2A6%2F7%2A7%2F8%2A8%2F9\" = \"3%2F9\" = \"1%2F3\"    (after canceling the terms in the numerator and denominator)\r\n" );
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document.write( "\"4%2F5%2A5%2F6%2A6%2F7%2A7%2F8%2A8%2F9%2A9%2F10\" = \"4%2F10\"       (after canceling the terms in the numerator and denominator)\r\n" );
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document.write( "Then \"log%283%2C+%283%2F4%2A4%2F5%2A5%2F6%2A6%2F7%2A7%2F8%2A8%2F9%29%29\" = \"log%283%2C+%281%2F3%29%29\" = -1   and\r\n" );
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document.write( "\"log%28%284%2F5%2A5%2F6%2A7%2F8%2A8%2F9%2A9%2F10%29%29\" = \"log%2810%2C+%284%2F5%2A5%2F6%2A7%2F8%2A8%2F9%2A9%2F10%29%29\" = \"log%2810%2C%284%2F10%29%29\" = \"log%2810%2C%284%29%29-1\" = \"2%2Alog%2810%2C%282%29%29-1\",\r\n" );
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document.write( "so your answer is \r\n" );
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document.write( ". . . = \"%28-1%29%2F%282%2Alog%2810%2C%282%29%29-1%29\" = \"1%2F%281-2%2Alog%2810%2C%282%29%29%29\".\r\n" );
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