document.write( "Question 1087358: An astronaut on Mars throws a ball into the air with an initial velocity of 30 feet per second from a platform 36 feet tall. Gravity on Mars is approximately -12 feet per second per second (-12). So, the height h of the ball t seconds after it is thrown is given by h6t2 30t 36. (a) How high is the ball after 3 seconds? \n" ); document.write( "

Algebra.Com's Answer #701652 by ikleyn(52793) $\"\"$ $\"About$

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document.write( "1.  The Mars atmosphere can hardly be called \"the air\".\r\n" );
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document.write( "    See this description of the Mars atmosphere from https://www.space.com/16903-mars-atmosphere-climate-weather.html :\r\n" );
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document.write( "        \"The atmosphere of Mars is about 100 times thinner than Earth's, and it is 95 percent carbon dioxide. Here's a breakdown of its composition:\r\n" );
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document.write( "        Carbon dioxide: 95.32 percent\r\n" );
document.write( "        Nitrogen: 2.7 percent\r\n" );
document.write( "        Argon: 1.6 percent\r\n" );
document.write( "        Oxygen: 0.13 percent\r\n" );
document.write( "        Carbon monoxide: 0.08 percent\r\n" );
document.write( "        Also, minor amounts of: water, nitrogen oxide, neon, hydrogen-deuterium-oxygen, krypton and xenon.\"\r\n" );
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document.write( "2.  The condition does not say if the ball was thrown vertically up or down, or either other way.\r\n" );
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document.write( "    The equation given also does not shed light on this subject.\r\n" );
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document.write( "3.  In the future, do not write equations without using signs. Please. Thanks.\r\n" );
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document.write( "4.  Still, if your equation is \r\n" );
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document.write( "    h(t) = -6*t^2 + 30t + 36,   (which means that the ball was thrown vertically up)\r\n" );
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document.write( "    then, to answer your question, simply substitute t= 3 into the right side and calculate h(t).\r\n" );
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