document.write( "Question 96380: The perimeter of a rectangular garden is 40 feet. If the length is 6 feet more than the width, what are the length and width of the garden?\r
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document.write( "So far I have. P = 2(l+w); P = 2(6+w)+w); 40 = 2(6+w)+w)\r
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document.write( "I don't know where to go from here. \n" );
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Algebra.Com's Answer #70164 by mathman409(67)![]() ![]() ![]() You can put this solution on YOUR website! 23=L 17=W \n" ); document.write( "P=40 \n" ); document.write( "L=W+6 \n" ); document.write( "w+l=40 \n" ); document.write( "now convert l into w \n" ); document.write( "w+(w+6)=40 \n" ); document.write( "2w+6=40 \n" ); document.write( "2w=40-6 \n" ); document.write( "2w=34 \n" ); document.write( "w=17 \n" ); document.write( "l=23 because 17(or w)+6=23 which is l \n" ); document.write( " |