document.write( "Question 1087366: solve for max/min f(x)=2sinx-1 on the interval [0,2 pi] \n" ); document.write( "

Algebra.Com's Answer #701631 by jim_thompson5910(35256) $\"\"$ $\"About$

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\n" ); document.write( "The largest that sin(x) can get is 1. So the max of f(x)=2*sin(x)-1 is f(x)=2*1-1=1
\n" ); document.write( "The smallest that sin(x) can get is -1. So the min of f(x)=2*sin(x)-1 is f(x)=2*(-1)-1=-3
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\n" ); document.write( "In summary:
\n" ); document.write( "Max = 1
\n" ); document.write( "Min = -3
\n" ); document.write( "Which is confirmed by the graph below
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\n" ); document.write( "Take note that each \"mountain\" peaks as high as y = 1, and each \"valley\" bottoms out as low as y = -3. The up and down pattern you see is repeated forever in both directions along the x axis.\r
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\n" ); document.write( "\n" ); document.write( "Graph generated by GeoGebra (free graphing software).
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