document.write( "Question 1087350: please help me to solve this dicemal into binary digit.
\n" ); document.write( "1) 32
\n" ); document.write( "2)11
\n" ); document.write( "3)29
\n" ); document.write( "4)50
\n" ); document.write( "5)36
\n" ); document.write( "

Algebra.Com's Answer #701617 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "decimal=> binary\r
\n" ); document.write( "\n" ); document.write( "Divide the decimal number to be converted by the value of the new base. In this case divide it by \"2\".\r
\n" ); document.write( "\n" ); document.write( "\"2\"|\"32\"
\n" ); document.write( "..\"16\"....\"0\" (reminder}
\n" ); document.write( "...\"8\"....\"0\"
\n" ); document.write( "...\"4\"....\"0\"
\n" ); document.write( "...\"2\"....\"0\"
\n" ); document.write( "...\"1\"....\"0\"\r
\n" ); document.write( "\n" ); document.write( "start with \"1\" and add all \"0\" \r
\n" ); document.write( "\n" ); document.write( "\"32\" = >\"100000\" \r
\n" ); document.write( "\n" ); document.write( "\"2\"|\"11\"
\n" ); document.write( "..\"5\"....\"1\"
\n" ); document.write( "...\"2\"....\"1\"
\n" ); document.write( "...\"2\"....\"0\"
\n" ); document.write( "...\"1\"\r
\n" ); document.write( "\n" ); document.write( "\"11\"=> \"1011\"\r
\n" ); document.write( "\n" ); document.write( "do same with rest of your numbers and you will get:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"29+\"= >\"11101\"\r
\n" ); document.write( "\n" ); document.write( "\"50\"= >\"110010\"\r
\n" ); document.write( "\n" ); document.write( "\"36\" => \"100100\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );