document.write( "Question 1087301: Solve the inequality. Write your answer in interval notation. \r
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document.write( "(x + 1)/((x + 5)(x - 2)) < or = 0 \n" );
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Algebra.Com's Answer #701610 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Break up the number line into regions using the critical values of the function, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So the four regions would be, \n" ); document.write( "Region 1: \n" ); document.write( "Region 2: \n" ); document.write( "Region 3: \n" ); document.write( "Region 4: \n" ); document.write( "For each region pick a point in the region (not an endpoint) and test the inequality. \n" ); document.write( "If true, it's part of the solution set. \n" ); document.write( "If false, it's not part of the solution set. \n" ); document.write( "The value is not important but whether it's negative or positive. \n" ); document.write( "Region 1: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "True \n" ); document.write( "Region 2: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "False \n" ); document.write( "Region 3: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "True \n" ); document.write( "Region 4: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "False \n" ); document.write( "So then, \n" ); document.write( "( \n" ); document.write( "Now dealing with the endpoints. \n" ); document.write( "Since the inequality includes an equal sign, it's allowed as long as it doesn't make the denominator equal to zero. \n" ); document.write( "In this case, \n" ); document.write( "Designate inclusion with brackets and exclusion with parentheses. \n" ); document.write( "( \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "The illustration shows the regions and the solution set (where the function lies on or below the x-axis) \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " |