document.write( "Question 1087320: Use the standard normal table to find the​ z-score that corresponds to the given percentile. If the area is not in the​ table, use the entry closest to the area. If the area is halfway between two​ entries, use the​ z-score halfway between the corresponding​ z-scores. If​ convenient, use technology to find the​ z-score.\r
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Algebra.Com's Answer #701606 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
you look for the area to the left of the z-score from the table.\r
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\n" ); document.write( "\n" ); document.write( "i found a z-score of.84 yielded .7995 area to the left of that z-score and i found a z-score of .85 yielded .8024 area to the left of that z-score.\r
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\n" ); document.write( "\n" ); document.write( ".7995 is closer to .80 than .8024, so the z-score chosen as the solution is a z-score of .84.\r
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\n" ); document.write( "\n" ); document.write( "the z-score of .84 is an addition of 0.8 in column 1 with .04 in column 7\r
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\n" ); document.write( "\n" ); document.write( "it's the intersection of the area in the row of .8 with the column of .04.\r
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\n" ); document.write( "\n" ); document.write( "this is shown in the following picture.\r
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\n" ); document.write( "\n" ); document.write( "the table i used is at http://www.stat.ufl.edu/~athienit/Tables/Ztable.pdf \n" ); document.write( "
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