document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1087315>Question 1087315</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is -9. One of the numbers minus twice the other number is 30. Find the two numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #701567 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=701567\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=-9<BR>\n" );
document.write( "y=-9-x<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "x-2y=30<BR>\n" );
document.write( "x-2(-9-x)=30<BR>\n" );
document.write( "x+18+2x=30<BR>\n" );
document.write( "3x=30-18<BR>\n" );
document.write( "3x=12<BR>\n" );
document.write( "x=12/3<BR>\n" );
document.write( "x=4<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "4-2y=30<BR>\n" );
document.write( "-2y=30-4<BR>\n" );
document.write( "y=26/-2<BR>\n" );
document.write( "y=-13<BR>\n" );
document.write( "------------ </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );