document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1087297>Question 1087297</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find a polynomial function of degree 3 with 3 and 1 as zeros.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #701561 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=701561\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x-1)(x-3) are two factors.  The third can't be complex, because those come in pairs.  Therefore, one of the two roots is repeated (a \"bounce\" on the graph).<BR>\n" );
document.write( "(x-1)^2(x-3)=(x^2-2x+1)(x-3)=x^3-5x^2+7x-3<BR>\n" );
document.write( "(x-1)(x-3)^2=(x^2-6x+9)(x-1)=x^3-7x^2+3x-9<BR>\n" );
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