document.write( "Question 96383: I am having trouble solving the following:\r
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document.write( "On the triangle, side A is x, side B is 16 and the hypotenuse is x+8. I can't seem to figure out where to start. \n" );
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Algebra.Com's Answer #70154 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! DOE THE EQUATION A^2+B^2=C^2 LOOK FAMILIAR???? \n" ); document.write( "A=A SIDE \n" ); document.write( "B=ANOTHER SIDE \n" ); document.write( "C=THE HYPOTENUSE \n" ); document.write( "HERE YOU HAVE A SIDE=X, SIDE 2=16 & THE HYPOTENUSE=X+8 \n" ); document.write( "X^2+18^2=(X+8)^2 NOW SOLVE FOR X \n" ); document.write( "X^2+324=X^2+16X+64 \n" ); document.write( "X^2-X^2-16X=64-324 \n" ); document.write( "-16X=-260 \n" ); document.write( "X=260/-16 \n" ); document.write( "X=16.25 \n" ); document.write( "16.25+8=24.25 IS THE LENGTH OF THE HYPOTENUSE. \n" ); document.write( "PROOF \n" ); document.write( "16.25^2+18^2=24.25^2 \n" ); document.write( "264.0625+324=588.0625 \n" ); document.write( "588.0625=588.0625 \n" ); document.write( " |