document.write( "Question 96379This question is from textbook Fundamentals of Alg and trig
\n" ); document.write( ": square root(2x-9)= 1/3\r
\n" ); document.write( "\n" ); document.write( "The first thing I did was square both sides to get rid of the radical. This leaves: 2x-9 = 1/9\r
\n" ); document.write( "\n" ); document.write( "Am I supposed to add nine to both sides? When I tried to do this I ended up with this: 2x= 1/9+ 9
\n" ); document.write( " 2x= 1/9+ 9/1
\n" ); document.write( "2x = 1/9+ 81/9
\n" ); document.write( "2x= 82/9\r
\n" ); document.write( "\n" ); document.write( "1. This doesn't seem right. How do I get rid of the 2?
\n" ); document.write( "

Algebra.Com's Answer #70153 by edjones(8007)\"\" \"About 
You can put this solution on YOUR website!
square root(2x-9)= 1/3
\n" ); document.write( "square both sides. 2x-9=1/9
\n" ); document.write( "multiply 9 times both sides. 18x-81=1
\n" ); document.write( "add 81 to both sides. 18x=82
\n" ); document.write( "divide both sides by 18 x=41/9
\n" ); document.write( "EdJones
\n" ); document.write( "
\n" );