document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1087175>Question 1087175</A>: <I><SPAN STYLE=\"word-break: break-all;\"> O is the centre of a circle HKL. |HK|=16cm, |HL|=10cm and the perpendicular from O to HK is 4cm. What is the length of the perpendicular from O to HL? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #701483 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=701483\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There is no HKL circle, a circle does not have sides or corners that you can name. Is HKL a triangle? Or are HK and KL chords on a circle?<BR>\n" );
document.write( "------------------------<BR>\n" );
document.write( "IF chords on a circle, first we find the radius:<BR>\n" );
document.write( "16/2 = 8 we have two triangles with long leg 8 and short leg 4. The hypotenuse of these triangles is our radius:<BR>\n" );
document.write( "sqrt(8^2+4^2) = 8.94<BR>\n" );
document.write( "--------------------------------<BR>\n" );
document.write( "Now we find distance to HL:<BR>\n" );
document.write( "10/2 = 5 this is the long leg of our two triangles. We know the hypotenuse, it's our radius 8.94. We have to find the other leg, the distance from O to HL. Pythagoras comes to the rescue again:<BR>\n" );
document.write( "sqrt(8.94^2-5^2) = 7.41 this is the distance from the center to HL </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );