document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=96367>Question 96367</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i find sloope of an equation that looks like this<BR>\n" );
document.write( "X-2/3y=1/4\r<BR>\n" );
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document.write( "and<BR>\n" );
document.write( ".<BR>\n" );
document.write( ".<BR>\n" );
document.write( ".<BR>\n" );
document.write( " 2X-5Y=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #70148 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=70148\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Y=mX+b IS THE LINE EQUATION WHERE m=SLOPE. NOW PUT YOUR EQUATION IN THIS FORM:<BR>\n" );
document.write( "X-2/3Y=1/4<BR>\n" );
document.write( "-2/3Y=-X+1/4<BR>\n" );
document.write( "Y=-X/(-2/3)+(1/4)/(-2/3) TO DIVIDE BY A FRACTION IN THE DENOMINATOR INVERT THE FRACTION IN THE DENOMINATOR & MULTIPLY BY THE NUMERATOR THUS:<BR>\n" );
document.write( "Y=-X(-3/2)+(1/4)(-3/2)<BR>\n" );
document.write( "Y=3X/2-3/8 THIS LINE HAS A SLOPE(m)=3/2 <BR>\n" );
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document.write( "2X-5Y=0<BR>\n" );
document.write( "-5Y=-2X<BR>\n" );
document.write( "Y=-2X/-5<BR>\n" );
document.write( "Y=2X/5 THIS LINE HAS A SLOPE(m)=2/5 </SPAN>\n" );
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