document.write( "Question 1087176: I AM STUCK NOW.\r
\n" ); document.write( "\n" ); document.write( "12. (A → B) & (A → C) ├ A→ (B & C)
\n" ); document.write( "1) (A → B) & (A → C) A
\n" ); document.write( "2) A PA
\n" ); document.write( "3) (A → B) 1 & O
\n" ); document.write( "4) (A → C) 1 & O\r
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Algebra.Com's Answer #701450 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
I'm assuming that you're given the premise (A -> B) & (A -> C) and you want to prove it leads to A -> (B & C)
\n" ); document.write( "If so, then here is one way to do the derivation using a conditional proof
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