document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1087134>Question 1087134</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure of the gas is inversely proportional to the volume of the gas. (1) suppose the pressure of a sample of air that occupies 0.106 cubic meter at 25 degrees Celsius is 70kPa. Find the constant of proportionality.<BR>\n" );
document.write( "(2) if the sample expands to a volume 0.4 cubic meter, find the new pressure </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #701414 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=701414\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the pressure of the gas is inversely proportional to the volume of the gas.\r<BR>\n" );
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document.write( "the general form of the equation of indirect variation is y = k/x\r<BR>\n" );
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document.write( "in your equation, y = p and x = v\r<BR>\n" );
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document.write( "p is the pressure of the gas.<BR>\n" );
document.write( "v is the volume of a sample of air.\r<BR>\n" );
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document.write( "the formula becomes p = k/v\r<BR>\n" );
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document.write( "when the volume of the gas is .106 cubic meters, the pressure is 70 kilo pascals.\r<BR>\n" );
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document.write( "the formula becomes 70 = k/.106\r<BR>\n" );
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document.write( "solve for k to get k = 70 * .16 = 7.42\r<BR>\n" );
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document.write( "now that you have solved for k, which is the constant of variation, you can solve the rest of the problem.\r<BR>\n" );
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document.write( "since k = 7.42, the equation becomes p = 7.42 / v\r<BR>\n" );
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document.write( "when v = .4 cubic meters, the equation becomes p = 7.42 / .4\r<BR>\n" );
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document.write( "solve for p to get p = 18.55 kilo pascals.\r<BR>\n" );
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document.write( "that should be your solution.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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