document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1087117>Question 1087117</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Celia is 2 times Jacque’s age now. Celia was 6 times Jacque’s age 9 years ago. What system of equations can be solved to find their ages? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #701399 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=701399\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> J age 9 years ago was x, and it is now x+9<BR>\n" );
document.write( "C's age 9 years ago was 6x, and it is now 6x+9<BR>\n" );
document.write( "But 6x+9=2(x+9), since C's age is twice J's age<BR>\n" );
document.write( "6x+9=2x+18<BR>\n" );
document.write( "4x=9<BR>\n" );
document.write( "x=2.25<BR>\n" );
document.write( "6x=13.5<BR>\n" );
document.write( "today,<BR>\n" );
document.write( "x=11.25, 9+2.25<BR>\n" );
document.write( "2x=22.5, 9+13.5 </SPAN>\n" );
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