document.write( "Question 1087083: A*sin(X)+B*sin(X+U)=C*sin(X+W), with C=sqrt(A^2+B^2+2*A*B*cos(U))
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Algebra.Com's Answer #701388 by Edwin McCravy(20086) $\"\"$ $\"About$

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A*sin(X)+B*sin(X+U)=C*sin(X+W), with C=sqrt(A^2+B^2+2*A*B*cos(U))
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document.write( "We are given that  tan(W)=(B*sin(U))/(A+B*cos(U)).\r\n" );
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document.write( "Since  and\r\n" );
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document.write( "we can draw a right triangle with B*sin(U) as the\r\n" );
document.write( "opposite side of angle W and A+B*cos(U) as the\r\n" );
document.write( "adjacent side of W:\r\n" );
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document.write( "We calculate the hypotenuse:\r\n" );
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document.write( "Notice that this result is the exact value that was given for C. So\r\n" );
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document.write( "Let's start with right side of what we have to prove:\r\n" );
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document.write( "Since  and ,\r\n" );
document.write( "we use the right triangle above to substitute for cos(W) and sin(W)\r\n" );
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document.write( "Edwin

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