document.write( "Question 1087074: The depreciated value VV of a machine is a linear function of time t in years. A machine that is purchased for $100000 today will be worth approximately $67681 in 33 years. Write the linear function V(t) that represents the value of the machine at a given time t.\r
\n" );
document.write( "\n" );
document.write( " My work---> 100,1000---->67,681 3yrs
\n" );
document.write( "67,681v+3=100,000 this is what I got but I'm not sure. \n" );
document.write( "
Algebra.Com's Answer #701359 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! I think you meant to say \"The depreciated value V\" instead of \"The depreciated value VV\". I changed the VV to V. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The value today is V = 100000 dollars when the time is t = 0, which is the starting time value. \n" ); document.write( "The value in 33 years, when t = 33, is V = 67681 dollars\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So we have two ordered pairs (0,100000) and (33,67681). I'm going to treat t as x, and treat V as y. So each ordered pair goes from the form (t,V) to (x,y). Using the (x,y) form we can use the slope formula\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First point = (x1,y1) = (0,100000) \n" ); document.write( "Second point = (x2,y2) = (33,67681) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the slope is roughly \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The y intercept is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So we go from \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The last thing to do is replace x with t and replace y with V(t) to get \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore the value function is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's check the function. Plug t = 0 into the function to get \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So that matches with the fact the initial value is $100,000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now plug in t = 33 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Which matches with the value after 33 years. So the answer is confirmed\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Side Note: if you use the fraction form for the slope then you won't run into rounding errors. The fact that we're rounding to 2 decimal places means that we don't have to worry about precision too much as long as the slope is expressed to 3 decimal places or more. You're probably wondering what the slope means? If so, then the slope is simply the rate of value decay or drop. In this case, the slope -979.3636 means the value V(t) is decreasing by $979.36 each year. The actual drop is a bit more than that but you can only round to the nearest hundredth for money problems like this. \n" ); document.write( " |