document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1087057>Question 1087057</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of a 90&#8203;% acid solution must be mixed with a 30&#8203;% acid solution to get 540 L of a 80&#8203;% acid&#8203; solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #701339 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=701339\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n and 540-n be the amounts of 90% acid and 30% acid, respectively. Then<BR>\n" );
document.write( ".9n+.3(540-n)=.8(540)=432<BR>\n" );
document.write( "Solve for n<BR>\n" );
document.write( "&#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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