document.write( "Question 1087036: A 121 in. long pipe is cut into three pieces such that the second piece is five in. more than the first piece, and the third piece is twelve in. more than four times the second piece. How long are the first, second, and third pieces. \n" ); document.write( "
Algebra.Com's Answer #701321 by addingup(3677)![]() ![]() You can put this solution on YOUR website! pieces are x, y, and z \n" ); document.write( "y = x+5 \n" ); document.write( "z = 4y+12 = 4(x+5)+12 = 4x+20+12 = 4x+32 \n" ); document.write( "---------------------------------------- \n" ); document.write( "x+y+z = 121 \n" ); document.write( "x+x+5+4x+32 = 121 \n" ); document.write( "6x+37 = 121 \n" ); document.write( "6x = 84 \n" ); document.write( "x = 14 \n" ); document.write( "y = x+5 = 14+5 = 19 \n" ); document.write( "z = 4x+32 = 4(14)+32 = 56+32 = 88 \n" ); document.write( "--------------------------- \n" ); document.write( "Check: \n" ); document.write( "14+19+88 = 121 \n" ); document.write( " \n" ); document.write( " |