document.write( "Question 1087028: If v = (2, -5), find the magnitude and direction angle of 2v. \n" ); document.write( "
Algebra.Com's Answer #701312 by ikleyn(52835)\"\" \"About 
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document.write( "The magnitude of the vector 2v is \"sqrt%284%5E2+%2B+%28-10%29%5E2%29\" = \"sqrt%2816+%2B+100%29\" = \"sqrt%28116%29\" = \"2%2Asqrt%2829%29\".\r\n" );
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document.write( "The direction angle of the vector 2v is the same as that of the vector v:\r\n" );
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document.write( "\"tan%28alpha%29\" = \"%28-5%29%2F2\" = -2.5.\r\n" );
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document.write( "Notice that the angle \"alpha\" lies in QIV.\r\n" );
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document.write( "Therefore,  \"alpha\" = \"arctan%28-2.5%29\",  or, which is the same,  \"alpha\" = \"-arctan%282.5%29\".\r\n" );
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