document.write( "Question 1082937: Two botas starts at the same point. One sail due east starting 10 A.M. at a constant rate of 20 kph. The other sail due south starting 11 A.M. at constant rate of 9 kph. How fast are they separating at noon?
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Algebra.Com's Answer #701297 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! The distance between them is the hypotenuse of a right triangle who's legs are measured by the rate of each boat. \n" ); document.write( " \n" ); document.write( "Let's measure time starting at 11 AM, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So then, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So at noon, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So now to find the rate of separation, implicitly differentiate the equation above with respect to time. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Substituting, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |