document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=96338>Question 96338</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0131808672/algebrahomeworkh>prentice hall mathematics algebra 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> three friends were born in consecutive years. the sum of their birth years is 5961. find the year in which each person was born.\r<BR>\n" );
document.write( "\n" );
document.write( "i need help solving this problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #70126 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=70126\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the year of birth of the youngest, then x+1 will be the year of birth of the next oldest and x+2 will be the year of birth of the eldest friend.<BR>\n" );
document.write( "So we need to find x.<BR>\n" );
document.write( "x+(x+1)+(x+2) = 5961<BR>\n" );
document.write( "3x+3 = 5961 Subtract 3 from both sides.<BR>\n" );
document.write( "3x = 5958 Divide both sides by 3.<BR>\n" );
document.write( "x = 1986<BR>\n" );
document.write( "x+1 = 1987<BR>\n" );
document.write( "x+2 = 1988<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "1986+1987+1988 = 5961 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );