document.write( "Question 1086877: 65% of men consider themselves football fans,you randomly select 8 men and ask each if he is a football fan.Find the probability that
\n" ); document.write( "1.at least 5 are football fans
\n" ); document.write( "2.less than five are football fans.
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Algebra.Com's Answer #701119 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's compute the binomial probabilities for k = 5 through k = 8 (where k is an integer)
\n" ); document.write( "For each case, the probability of success is p = 0.65 and the sample size is n = 8\r
\n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------
\n" ); document.write( "For k = 5, we have this combination
\n" ); document.write( "n C k = (n!)/(k!*(n-k)!)
\n" ); document.write( "8 C 5 = (8!)/(5!*(8-5)!)
\n" ); document.write( "8 C 5 = (8!)/(5!*3!)
\n" ); document.write( "8 C 5 = (8*7*6*5!)/(5!*3!)
\n" ); document.write( "8 C 5 = (8*7*6)/(3!)
\n" ); document.write( "8 C 5 = (8*7*6)/(3*2*1)
\n" ); document.write( "8 C 5 = 336/6
\n" ); document.write( "8 C 5 = 56\r
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\n" ); document.write( "\n" ); document.write( "Leading to this binomial probability
\n" ); document.write( "P(X = k) = (n C k)*(p)^(k)*(1-p)^(n-k)
\n" ); document.write( "P(X = 5) = (8 C 5)*(0.65)^(5)*(1-0.65)^(8-5)
\n" ); document.write( "P(X = 5) = (8 C 5)*(0.65)^(5)*(0.35)^(3)
\n" ); document.write( "P(X = 5) = (56)*(0.65)^(5)*(0.35)^3
\n" ); document.write( "P(X = 5) = (56)*(0.1160290625)*(0.042875)
\n" ); document.write( "P(X = 5) = 0.2785857790625\r
\n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------
\n" ); document.write( "For k = 6, we have this combination
\n" ); document.write( "n C k = (n!)/(k!*(n-k)!)
\n" ); document.write( "8 C 6 = (8!)/(6!*(8-6)!)
\n" ); document.write( "8 C 6 = (8!)/(6!*2!)
\n" ); document.write( "8 C 6 = (8*7*6!)/(6!*2!)
\n" ); document.write( "8 C 6 = (8*7)/(2!)
\n" ); document.write( "8 C 6 = (8*7)/(2*1)
\n" ); document.write( "8 C 6 = 56/2
\n" ); document.write( "8 C 6 = 28\r
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\n" ); document.write( "\n" ); document.write( "Leading to this binomial probability
\n" ); document.write( "P(X = k) = (n C k)*(p)^(k)*(1-p)^(n-k)
\n" ); document.write( "P(X = 6) = (8 C 6)*(0.65)^(6)*(1-0.65)^(8-6)
\n" ); document.write( "P(X = 6) = (8 C 6)*(0.65)^(6)*(0.35)^(2)
\n" ); document.write( "P(X = 6) = (28)*(0.65)^(6)*(0.35)^2
\n" ); document.write( "P(X = 6) = (28)*(0.075418890625)*(0.1225)
\n" ); document.write( "P(X = 6) = 0.25868679484375\r
\n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------
\n" ); document.write( "For k = 7, we have this combination
\n" ); document.write( "n C k = (n!)/(k!*(n-k)!)
\n" ); document.write( "8 C 7 = (8!)/(7!*(8-7)!)
\n" ); document.write( "8 C 7 = (8!)/(7!*1!)
\n" ); document.write( "8 C 7 = (8*7!)/(7!*1!)
\n" ); document.write( "8 C 7 = (8)/(1!)
\n" ); document.write( "8 C 7 = (8)/(1)
\n" ); document.write( "8 C 7 = 8/1
\n" ); document.write( "8 C 7 = 8\r
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\n" ); document.write( "\n" ); document.write( "Leading to this binomial probability
\n" ); document.write( "P(X = k) = (n C k)*(p)^(k)*(1-p)^(n-k)
\n" ); document.write( "P(X = 7) = (8 C 7)*(0.65)^(7)*(1-0.65)^(8-7)
\n" ); document.write( "P(X = 7) = (8 C 7)*(0.65)^(7)*(0.35)^(1)
\n" ); document.write( "P(X = 7) = (8)*(0.65)^(7)*(0.35)^1
\n" ); document.write( "P(X = 7) = (8)*(0.04902227890625)*(0.35)
\n" ); document.write( "P(X = 7) = 0.1372623809375\r
\n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------
\n" ); document.write( "For k = 8, we have this combination
\n" ); document.write( "n C k = (n!)/(k!*(n-k)!)
\n" ); document.write( "8 C 8 = (8!)/(8!*(8-8)!)
\n" ); document.write( "8 C 8 = (8!)/(8!*0!)
\n" ); document.write( "8 C 8 = (1)/(1*0!)
\n" ); document.write( "8 C 8 = (1)/(1*1)
\n" ); document.write( "8 C 8 = (1)/(1)
\n" ); document.write( "8 C 8 = 1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Leading to this binomial probability
\n" ); document.write( "P(X = k) = (n C k)*(p)^(k)*(1-p)^(n-k)
\n" ); document.write( "P(X = 8) = (8 C 8)*(0.65)^(8)*(1-0.65)^(8-8)
\n" ); document.write( "P(X = 8) = (8 C 8)*(0.65)^(8)*(0.35)^(0)
\n" ); document.write( "P(X = 8) = (1)*(0.65)^(8)*(0.35)^0
\n" ); document.write( "P(X = 8) = (1)*(0.0318644812890625)*(1)
\n" ); document.write( "P(X = 8) = 0.0318644812890625\r
\n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "We do not need to compute the probabilities for k = 0 to k = 4, but for the sake of completeness the probabilities are shown in the table below\r
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\n" ); document.write( "\n" ); document.write( "Full Binomial Distribution Table
\n" ); document.write( "\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( "
X = kP(X = k)
00.0002251875390625
10.0033456434375
20.02174668234375
30.0807733915625
40.187509658984375
50.2785857790625
60.25868679484375
70.1372623809375
80.0318644812890625

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\n" ); document.write( "\n" ); document.write( "We'll use that table to answer problem 1. Add up the probabilities for k = 5, k = 6, k = 7, k = 8 to get
\n" ); document.write( "\"P%28X+%3E=+5%29+=+P%28X+=+5%29%2BP%28X+=+6%29%2BP%28X+=+7%29%2BP%28X+=+8%29\"
\n" ); document.write( "\"P%28X+%3E=+5%29+=+0.2785857790625%2B0.25868679484375%2B0.1372623809375%2B0.0318644812890625\"
\n" ); document.write( "\"P%28X+%3E=+5%29+=+0.70639943613281\"
\n" ); document.write( "Answer for problem one: 0.70639943613281
\n" ); document.write( "Round that however you need to\r
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\n" ); document.write( "\n" ); document.write( "The events \"less than 5\" and \"at least 5\" are complementary. One or the other must happen. Therefore their probabilities add to 1
\n" ); document.write( "\"P%28X+%3C+5%29+%2B+P%28X+%3E=+5%29+=+1\"
\n" ); document.write( "\"P%28X+%3C+5%29+=+1-P%28X+%3E=+5%29\"\r
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\n" ); document.write( "\n" ); document.write( "Use the result from problem 1 to get
\n" ); document.write( "\"P%28X+%3C+5%29+=+1-P%28X+%3E=+5%29\"
\n" ); document.write( "\"P%28X+%3C+5%29+=+1-0.70639943613281\"
\n" ); document.write( "\"P%28X+%3C+5%29+=+0.29360056386719\"
\n" ); document.write( "Answer for problem two: 0.29360056386719
\n" ); document.write( "Round that however you need to
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