document.write( "Question 1086875: 2x^2 + y^2 = 4
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Algebra.Com's Answer #701118 by ikleyn(52803)\"\" \"About 
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document.write( "You are given that  \r\n" );
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document.write( "\"2x%5E2+%2B+y%5E2\" = \"4\",    (1)\r\n" );
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document.write( "and they ask you to find max and min of\r\n" );
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document.write( "\"4x+%2B+y%5E2\".          (2)\r\n" );
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document.write( "    Notice that, due to (1), the domain for x is the set of real numbers  \"-sqrt%282%29\" <= x <= \"sqrt%282%29\".\r\n" );
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document.write( "From (1), you have \"y%5E2\" = \"4+-+2x%5E2\".   Substitute it into (2), replacing  \"y%5E2\".  You will get\r\n" );
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document.write( "\"4x+%2B+y%5E2\" = \"4x+%2B+4+-+2x%5E2\" = \"-2%2A%28x%5E2+-+2x%29+%2B+4%29\" = (completing the square) = \"-2%2A%28x%5E2+-+2x+%2B+1%29+%2B+2+%2B+4%29\" = \"-2%2A%28x-1%29%5E2+%2B+6\".\r\n" );
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document.write( "Thus the maximum of  \"4x+%2B+y%5E2\"  is equal to  6  and it is achieved at x = 1.\r\n" );
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document.write( "Or, more precisely, the maximum of  \"4x+%2B+y%5E2\"  is achieved at the points  (x,y) = (\"1\",\"sqrt%282%29\")  and  (x,y) = (\"1\",\"-sqrt%282%29\").\r\n" );
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document.write( "The plot below shows the graph  f(x) = \"-2%2A%28x-1%29%5E2+%2B+6\" in the interval  [\"-sqrt%282%29\",\"sqrt%282%29\"].\r\n" );
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document.write( "Plot  f(x) = \"-2%2A%28x-1%29%5E2+%2B+6\"\r\n" );
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document.write( "The minimum is at x = \"-sqrt%282%29\" and is equal to \"-2%2A%28-sqrt%282%29-1%29%5E2+%2B+6\" = \"-2%2A%281%2Bsqrt%282%29%29%5E2+%2B+6\" = -5.65 (approximately).\r\n" );
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