document.write( "Question 1086830: Please help me solving this quadratic equation system:
\n" ); document.write( "\"+x%5E2%2B2%2Ax-y%2B4=0+\"
\n" ); document.write( "\"+3%2Ax-y%2B6=0+\"
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Algebra.Com's Answer #701067 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Please help me solving this quadratic equation system:
\n" ); document.write( "\"+x%5E2%2B2%2Ax-y%2B4=0+\"
\n" ); document.write( "\"+3%2Ax-y%2B6=0+\"
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\"x%5E2+%2B+2x+-+y+%2B+4+=+0\" ------- eq (i)
\n" ); document.write( "3x - y + 6 = 0 ======> y = 3x + 6 ------ eq (ii)
\n" ); document.write( "\"x%5E2+%2B+2x+-+%283x+%2B+6%29+%2B+4+=+0\" -------- Substituting 3x + 6 for y in eq (i)
\n" ); document.write( "\"x%5E2+%2B+2x+-+3x+-+6+%2B+4+=+0\"
\n" ); document.write( "\"x%5E2+-+x+-+2+=+0\"
\n" ); document.write( "(x - 2)(x + 1) = 0
\n" ); document.write( "x = 2 OR x = - 1\r
\n" ); document.write( "\n" ); document.write( "y = 3(2) + 6 ------- Substituting 2 for x in eq (ii)
\n" ); document.write( "y = 6 + 6, or 12
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\n" ); document.write( "\n" ); document.write( "y = 3(- 1) + 6 ------- Substituting - 1 for x in eq (ii)
\n" ); document.write( "y = - 3 + 6, or 3
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