document.write( "Question 1086784: Please help me to solve this\r
\n" ); document.write( "\n" ); document.write( "a factory supervisor finds that 20 percent of the bolts produced by a machine will be defective . If 5 bolts are chosen at random,find the probability that at most 2 bolts will be defective.\r
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Algebra.Com's Answer #701020 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Binomial Distribution:
\n" ); document.write( "Probability of defect = p = 20% = 20/100 = 0.20 (use the decimal form)
\n" ); document.write( "sample size = n = 5\r
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\n" ); document.write( "\n" ); document.write( "We need to compute the probabilities for k = 0, k = 1, k = 2
\n" ); document.write( "\"At most 2\" means \"2 is the ceiling\" or \"2 is the highest we can go\"\r
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\n" ); document.write( "For k = 0, we would have this combination
\n" ); document.write( "n C k = (n!)/(k!*(n-k)!)
\n" ); document.write( "5 C 0 = (5!)/(0!*(5-0)!)
\n" ); document.write( "5 C 0 = (5!)/(0!*5!)
\n" ); document.write( "5 C 0 = (1)/(0!*1)
\n" ); document.write( "5 C 0 = (1)/(1)
\n" ); document.write( "5 C 0 = 1\r
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\n" ); document.write( "\n" ); document.write( "Leading to this binomial probability
\n" ); document.write( "P(X = k) = (n C k)*(p)^(k)*(1-p)^(n-k)
\n" ); document.write( "P(X = 0) = (5 C 0)*(0.2)^(0)*(1-0.2)^(5-0)
\n" ); document.write( "P(X = 0) = (5 C 0)*(0.2)^(0)*(0.8)^(5)
\n" ); document.write( "P(X = 0) = (1)*(0.2)^(0)*(0.8)^5
\n" ); document.write( "P(X = 0) = (1)*(1)*(0.32768)
\n" ); document.write( "P(X = 0) = 0.32768\r
\n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------
\n" ); document.write( "For k = 1, we would have this combination
\n" ); document.write( "n C k = (n!)/(k!*(n-k)!)
\n" ); document.write( "5 C 1 = (5!)/(1!*(5-1)!)
\n" ); document.write( "5 C 1 = (5!)/(1!*4!)
\n" ); document.write( "5 C 1 = (5*4!)/(1!*4!)
\n" ); document.write( "5 C 1 = (5)/(1!)
\n" ); document.write( "5 C 1 = (5)/(1)
\n" ); document.write( "5 C 1 = 5/1
\n" ); document.write( "5 C 1 = 5\r
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\n" ); document.write( "\n" ); document.write( "Leading to this binomial probability
\n" ); document.write( "P(X = k) = (n C k)*(p)^(k)*(1-p)^(n-k)
\n" ); document.write( "P(X = 1) = (5 C 1)*(0.2)^(1)*(1-0.2)^(5-1)
\n" ); document.write( "P(X = 1) = (5 C 1)*(0.2)^(1)*(0.8)^(4)
\n" ); document.write( "P(X = 1) = (5)*(0.2)^(1)*(0.8)^4
\n" ); document.write( "P(X = 1) = (5)*(0.2)*(0.4096)
\n" ); document.write( "P(X = 1) = 0.4096\r
\n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------
\n" ); document.write( "For k = 2, we would have this combination
\n" ); document.write( "n C k = (n!)/(k!*(n-k)!)
\n" ); document.write( "5 C 2 = (5!)/(2!*(5-2)!)
\n" ); document.write( "5 C 2 = (5!)/(2!*3!)
\n" ); document.write( "5 C 2 = (5*4*3!)/(2!*3!)
\n" ); document.write( "5 C 2 = (5*4)/(2!)
\n" ); document.write( "5 C 2 = (5*4)/(2*1)
\n" ); document.write( "5 C 2 = 20/2
\n" ); document.write( "5 C 2 = 10\r
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\n" ); document.write( "\n" ); document.write( "Leading to this binomial probability
\n" ); document.write( "P(X = k) = (n C k)*(p)^(k)*(1-p)^(n-k)
\n" ); document.write( "P(X = 2) = (5 C 2)*(0.2)^(2)*(1-0.2)^(5-2)
\n" ); document.write( "P(X = 2) = (5 C 2)*(0.2)^(2)*(0.8)^(3)
\n" ); document.write( "P(X = 2) = (10)*(0.2)^(2)*(0.8)^3
\n" ); document.write( "P(X = 2) = (10)*(0.04)*(0.512)
\n" ); document.write( "P(X = 2) = 0.2048\r
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\n" ); document.write( "\n" ); document.write( "If we keep going, we would get this full Binomial distribution\r
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( "
X = kP(X = k)
00.32768
10.4096
20.2048
30.0512
40.0064
50.00032
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\n" ); document.write( "\n" ); document.write( "Now add up the probabilities for k = 0, k = 1, k = 2.\r
\n" ); document.write( "\n" ); document.write( "\"P%28X+%3C=+2%29+=+P%28X+=+0%29%2BP%28X+=+1%29%2BP%28X+=+2%29\"
\n" ); document.write( "\"P%28X+%3C=+2%29+=+0.32768%2B0.4096%2B0.2048\"
\n" ); document.write( "\"P%28X+%3C=+2%29+=+0.94208\"\r
\n" ); document.write( "\n" ); document.write( "Answer: 0.94208
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