document.write( "Question 1086778: use a difference of squares method to solve the following:
\n" ); document.write( "\"x%5E2-5x%2B3=x%28x-5%29%2B3=0\" then substitute A=x-2.5
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Algebra.Com's Answer #701016 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
this dosn't look like a difference of square method.\r
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\n" ); document.write( "\n" ); document.write( "different of square is (a^2 - b^2) = (a-b) * (a+b)\r
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\n" ); document.write( "\n" ); document.write( "i don't see that in this problem.\r
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\n" ); document.write( "\n" ); document.write( "your equation is x^2 - 5x + 3 = 0.\r
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\n" ); document.write( "\n" ); document.write( "the roots are not integers.\r
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\n" ); document.write( "\n" ); document.write( "you can solve this graphically or by use of the quadratic formula, but not by difference of squares as far as i can tell.\r
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\n" ); document.write( "\n" ); document.write( "i used the quadratic formula and got the following roots:\r
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\n" ); document.write( "\n" ); document.write( "x = 4.302775637732 or x = 0.69722436226801\r
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\n" ); document.write( "\n" ); document.write( "neither one of them appears to be rational.\r
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\n" ); document.write( "\n" ); document.write( "you may have meant to solve by squaring.\r
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\n" ); document.write( "\n" ); document.write( "in that case, you would get:\r
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\n" ); document.write( "\n" ); document.write( "x^2 - 5x + 3 = (x-2.5)^2 - 2.5^2 + 3 = 0\r
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\n" ); document.write( "\n" ); document.write( "this becomes (x-2.5)^2 - 6.25 + 3 = 0\r
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\n" ); document.write( "\n" ); document.write( "this becomes (x-2.5)^2 - 3.25 = 0\r
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\n" ); document.write( "\n" ); document.write( "this becomes (x-2.5)^2 = 3.25\r
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\n" ); document.write( "\n" ); document.write( "take the square root of both sides to get:\r
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\n" ); document.write( "\n" ); document.write( "x-2.5 = plus or minus sqrt(3.25)\r
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\n" ); document.write( "\n" ); document.write( "this becomes x - 2.5 = plus or mionus 1.802775638\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get the same thing i got above.\r
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\n" ); document.write( "\n" ); document.write( "this method is not calloed difference of squares.\r
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\n" ); document.write( "\n" ); document.write( "it's called completing the square method.\r
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\n" ); document.write( "\n" ); document.write( "the general principal is.\r
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\n" ); document.write( "\n" ); document.write( "start with x^2 - 5x + 3 = 0\r
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\n" ); document.write( "\n" ); document.write( "move the 3 over to the other side of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "x^2 - 5x = -3\r
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\n" ); document.write( "\n" ); document.write( "take half the coefficient of the x term and then square it as shown below:\r
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\n" ); document.write( "\n" ); document.write( "(x-2.5)^2 - (2.5)^2 = -3\r
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\n" ); document.write( "\n" ); document.write( "move the - 2.5)^2 to the other side of the equation t0o get:\r
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\n" ); document.write( "\n" ); document.write( "(x-2.5)^2 = (2.5)^2 - 3\r
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\n" ); document.write( "\n" ); document.write( "take the square root of both sides of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "x-2.5 = plus or minus square root of ((2.5)^2 - 3)\r
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\n" ); document.write( "\n" ); document.write( "solve for x as i did above.\r
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\n" ); document.write( "\n" ); document.write( "here's a good reference on completing the square method.\r
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\n" ); document.write( "\n" ); document.write( "http://www.purplemath.com/modules/sqrquad.htm\r
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\n" ); document.write( "\n" ); document.write( "here's a good reference on difference of squares method.\r
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\n" ); document.write( "\n" ); document.write( "http://www.purplemath.com/modules/specfact.htm\r
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