document.write( "Question 96290: A bank loaned out $12,000, part of it at the rate of 8% per year and the rest at the rate of 18% per year. If the interest recieved totaled $1,000, how much was loaned at 8%?
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Algebra.Com's Answer #70100 by checkley71(8403)\"\" \"About 
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.08x+.18(10000-x)=1000
\n" ); document.write( ".08x+1800-.18x=1000
\n" ); document.write( "-.1x=1000-1800
\n" ); document.write( "-.1x=-800
\n" ); document.write( "x=-800/-.1
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\n" ); document.write( "x=8000 amount loaned @ 8%.
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\n" ); document.write( "10000-8000=2000 loaned @ 18%.
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\n" ); document.write( "8000*.08+2000*.18=1000
\n" ); document.write( "640+360=1000
\n" ); document.write( "1000=1000
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