document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1086758>Question 1086758</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of the sides of two squares are 4cm and 2cm. Find, in its simplest form, the ratio of their (i) perimeters (ii)areas </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #700973 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=700973\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter is directly proportional so if the side doubles the perimeter doubles<BR>\n" );
document.write( "The perimeter =4s, 8 cm for the first square and 16 for the second.<BR>\n" );
document.write( "The area is proportional to the square of the side, so the area is 4 times as large for the second.<BR>\n" );
document.write( "area of the first=s^2=4 cm^2; area of second is 16 cm^2, 4 times as much. </SPAN>\n" );
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