document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1086699>Question 1086699</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of three numbers is 150. The second number is thrice the first, and the third is ten less than twice the second. Find all numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #700969 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=700969\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let your numbers be l, m, and n. Then:<BR>\n" );
document.write( "l+m+n=150<BR>\n" );
document.write( "m=31<BR>\n" );
document.write( "n=2(31)-10<BR>\n" );
document.write( "So:<BR>\n" );
document.write( "l+31+61-10=150<BR>\n" );
document.write( "10l=160<BR>\n" );
document.write( "l=16<BR>\n" );
document.write( "m=48<BR>\n" );
document.write( "n=86<BR>\n" );
document.write( "&#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );