document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1086705>Question 1086705</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two dice are rolled together. What is the probability that:<BR>\n" );
document.write( "a)The first die shows 1 or the second die shows 4?<BR>\n" );
document.write( "B)The first die shows odd number and the second die shows prime number?<BR>\n" );
document.write( "c)The first die shows odd number or the second die shows prime number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #700929 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=700929\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 6 * 6 = 36 possible outcomes<BR>\n" );
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document.write( "a) Probability(P) of 1st die is a 1 is 6/36 and P of 2nd die is a 4 is 6/36<BR>\n" );
document.write( "P(rolling a 1 or a 4)) = (6/36) + (6/36) = (1/6) + (1/6) = 2/6 = 1/3<BR>\n" );
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document.write( "b) P(1st die is odd number) = 18/36 = 1/2, P(2nd die is a prime numbers) = 24/36 = 2/3<BR>\n" );
document.write( "---Note prime numbers are 2, 3, 5<BR>\n" );
document.write( "P(rolling odd number and a prime number) = (1/2) * (2/3) = 2/6 = 1/3<BR>\n" );
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document.write( "c) P(rolling odd number or a prime number) = (18/36) + (18/36) - (9/36) = 3/4<BR>\n" );
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document.write( "---Note we have to subtract the 9 events where the first die is a 1, 3 or 5 and second die is 2, 3, 5 since we already counted them<BR>\n" );
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document.write( " </SPAN>\n" );
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