document.write( "Question 1086635:  The United Package Service has a policy that states if a package is delivered late they will reimburse their shipping fees.  They deliver packages late only 5% of the time.  If a delivery person has 7 deliveries one day, what is the probability that at most 1 package is arriving late?  Round your answer to the nearest ten-thousandth. \n" ); document.write( "
Algebra.Com's Answer #700883 by mathmate(429)\"\" \"About 
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Question:
\n" ); document.write( "The United Package Service has a policy that states if a package is delivered late they will reimburse their shipping fees.  They deliver packages late only 5% of the time.  If a delivery person has 7 deliveries one day, what is the probability that at most 1 package is arriving late?  Round your answer to the nearest ten-thousandth.
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\n" ); document.write( "Solution:
\n" ); document.write( "To determine if the problem can be modelled using the binomial distribution, we need to examine the following criteria:
\n" ); document.write( "1. Bernoulli trials, i.e. exactly two possible outcomes (Late or not late)
\n" ); document.write( "2. Number of trials is known before experiment, i.e. independent of outcomes (7 per day)
\n" ); document.write( "3. All trials are independent of each other (assumed true)
\n" ); document.write( "4. Probability of success is known, and remain constant throughout trials (p=5%=0.05)
\n" ); document.write( "Since all the criteria are satisfied, binomial distribution will be used.
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\n" ); document.write( "The probability of x successes out of N trials each with probability of success p is given by
\n" ); document.write( "P(x)=C(N,x)(p^x)(1-p)^(N-x)
\n" ); document.write( "where
\n" ); document.write( "C(N,x) is number of combinations of selecting x objects out of N.\r
\n" ); document.write( "\n" ); document.write( "p=0.05
\n" ); document.write( "n=7
\n" ); document.write( "x=0 and x=1
\n" ); document.write( "P(\"at most one package late\") =P(0)+P(1)
\n" ); document.write( "=C(7,0)*0.05^0*(1-0.05)^7+C(7,1)*0.05^1*(1-0.05)^6
\n" ); document.write( "=0.6983+0.2573
\n" ); document.write( "=0.9556
\n" ); document.write( "Probability of at most one delivery late is 0.9556.
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