document.write( "Question 1086635: The United Package Service has a policy that states if a package is delivered late they will reimburse their shipping fees. They deliver packages late only 5% of the time. If a delivery person has 7 deliveries one day, what is the probability that at most 1 package is arriving late? Round your answer to the nearest ten-thousandth. \n" ); document.write( "
| Algebra.Com's Answer #700883 by mathmate(429)     You can put this solution on YOUR website! Question: \n" ); document.write( "The United Package Service has a policy that states if a package is delivered late they will reimburse their shipping fees. They deliver packages late only 5% of the time. If a delivery person has 7 deliveries one day, what is the probability that at most 1 package is arriving late? Round your answer to the nearest ten-thousandth. \n" ); document.write( " \n" ); document.write( "Solution: \n" ); document.write( "To determine if the problem can be modelled using the binomial distribution, we need to examine the following criteria: \n" ); document.write( "1. Bernoulli trials, i.e. exactly two possible outcomes (Late or not late) \n" ); document.write( "2. Number of trials is known before experiment, i.e. independent of outcomes (7 per day) \n" ); document.write( "3. All trials are independent of each other (assumed true) \n" ); document.write( "4. Probability of success is known, and remain constant throughout trials (p=5%=0.05) \n" ); document.write( "Since all the criteria are satisfied, binomial distribution will be used. \n" ); document.write( " \n" ); document.write( "The probability of x successes out of N trials each with probability of success p is given by \n" ); document.write( "P(x)=C(N,x)(p^x)(1-p)^(N-x) \n" ); document.write( "where \n" ); document.write( "C(N,x) is number of combinations of selecting x objects out of N.\r \n" ); document.write( "\n" ); document.write( "p=0.05 \n" ); document.write( "n=7 \n" ); document.write( "x=0 and x=1 \n" ); document.write( "P(\"at most one package late\") =P(0)+P(1) \n" ); document.write( "=C(7,0)*0.05^0*(1-0.05)^7+C(7,1)*0.05^1*(1-0.05)^6 \n" ); document.write( "=0.6983+0.2573 \n" ); document.write( "=0.9556 \n" ); document.write( "Probability of at most one delivery late is 0.9556. \n" ); document.write( " |