document.write( "Question 1086637: The letters of the word STATISTICS are arranged randomly.\r
\n" ); document.write( "\n" ); document.write( "What is the probability the arrangement will start and end with an S?
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Algebra.Com's Answer #700867 by KMST(5328)\"\" \"About 
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There are 10 characters, and 3 of them are S,
\n" ); document.write( "so when picking your first character,
\n" ); document.write( "the probability of picking an S would be
\n" ); document.write( "\"3%2F10\" .
\n" ); document.write( "After that, there would be 9 characters left, including two S characters.
\n" ); document.write( "Then the probability id picking an S for last character,
\n" ); document.write( "after having picked an S for fist character would be \"2%2F9\" .
\n" ); document.write( "So, the probability that a rearrangements of the letters in STATISTICS
\n" ); document.write( "would start and end with S is
\n" ); document.write( "\"%283%2F10%29%282%2F9%29=highlight%282%2F30%29\" .
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\n" ); document.write( "ANOTHER WAY:
\n" ); document.write( "There are \"10%21=10%2A9%2A8%2A7%2A6%2A5%2A4%2A3%2A2\" possible arrangements.
\n" ); document.write( "If you labeled the letters so as to distinguish one S from another S, one T from another T, and one I from the other I, you would see that many different arrangements.
\n" ); document.write( "If we are to make arrangements starting and ending with S,
\n" ); document.write( "there are \"3%2A2\" ways to choose which S will be at either end,
\n" ); document.write( "and there are \"8%21=8%2A7%2A6%2A5%2A4%2A3%2A2\" ways to arrange the 8 middle characters.
\n" ); document.write( "That makes for \"3%2A8%21\" different arrangements starting and ending wit S,
\n" ); document.write( "out of the \"10%21\" possible arrangements.
\n" ); document.write( "That is
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