document.write( "Question 1086581: You are estimating the cost of engine overhauls. A sample of 49 repairs showed an average overhaul of 285 hours with a standard deviation of 60 hours. Calculate a 95% confidence interval for the average overhaul. (Carry intermediate calculations to three decimal places.)\r
\n" ); document.write( "\n" ); document.write( " a. 271.00 ≤ μ ≤ 299.00
\n" ); document.write( " b. 268.20 ≤ μ ≤ 301.80
\n" ); document.write( " c. 281.61 ≤ μ ≤ 288.39
\n" ); document.write( " d. 284.52 ≤ μ ≤ 285.48 \r
\n" ); document.write( "\n" ); document.write( "You are estimating the cost of a personnel shelter and you have collected cost data on 10 shelters. The mean cost was $16,693. The median cost is $17,402. There is a range in the cost of $10,095. The standard deviation is $2,270. If you use the average cost of the shelters as your estimate, then, on average:\r
\n" ); document.write( "\n" ); document.write( " a. You could expect to be off by $10,095.
\n" ); document.write( " b. You could expect to be off by 20.42%.
\n" ); document.write( " c. You could expect to be off by 13.60%.
\n" ); document.write( " d. You could expect to be off by $340.90.
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Algebra.Com's Answer #700854 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "z = 1.960 (z critical value at 95% confidence)
\n" ); document.write( "n = 49
\n" ); document.write( "xbar = 285
\n" ); document.write( "s = 60\r
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\n" ); document.write( "\n" ); document.write( "The lower limit of the confidence interval is
\n" ); document.write( "L = xbar - z*(s/sqrt(n))
\n" ); document.write( "L = 285 - 1.96*(60/sqrt(49))
\n" ); document.write( "L = 285 - 1.96*(60/7)
\n" ); document.write( "L = 285 - 1.96*(8.57142857142857)
\n" ); document.write( "L = 285 - 16.8
\n" ); document.write( "L = 268.2\r
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\n" ); document.write( "\n" ); document.write( "The upper limit of the confidence interval is
\n" ); document.write( "U = xbar + z*(s/sqrt(n))
\n" ); document.write( "U = 285 + 1.96*(60/sqrt(49))
\n" ); document.write( "U = 285 + 1.96*(60/7)
\n" ); document.write( "U = 285 + 1.96*(8.57142857142857)
\n" ); document.write( "U = 285 + 16.8
\n" ); document.write( "U = 301.8\r
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\n" ); document.write( "\n" ); document.write( "(L,U) = (268.2,301.8)\r
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\n" ); document.write( "\n" ); document.write( "The final answer is choice B) 268.20 < µ < 301.80
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