document.write( "Question 1086590: a man has two sums of money at interest, one at 3% and the other is 3 1/2%. his annual income from the two investments is php999. if he could get 3 1/2% on both of his money, he will earn php1092. how much has he invented at each rate \n" ); document.write( "
Algebra.Com's Answer #700822 by ankor@dixie-net.com(22740)\"\" \"About 
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a man has two sums of money at interest, one at 3% and the other is 3 1/2%. his annual income from the two investments is php999. if he could get 3 1/2% on both of his money, he will earn php1092. how much has he invented at each rate
\n" ); document.write( ":
\n" ); document.write( "let a = the 1st amt
\n" ); document.write( "let b = the 2nd amt
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each scenario
\n" ); document.write( ".03a + .035b = 999
\n" ); document.write( ".035a + .035b = 1092
\n" ); document.write( ":
\n" ); document.write( "Subtract the 1st equation from the 2nd equation
\n" ); document.write( ".035a + .035b = 1092
\n" ); document.write( ".03a + .035b = 999
\n" ); document.write( "-----------------------subtraction eliminates b, find a
\n" ); document.write( ".005a = 93
\n" ); document.write( "a = 93/.005
\n" ); document.write( "a = $18600 is the 1st amt
\n" ); document.write( ":
\n" ); document.write( "Find b
\n" ); document.write( ".03(18600) + .035b = 999
\n" ); document.write( "558 + .035b = 999
\n" ); document.write( ".035b = 999 - 558
\n" ); document.write( ".035b = 441
\n" ); document.write( "b = 441/.035
\n" ); document.write( "b = $12600 is the 2nd amt
\n" ); document.write( ":
\n" ); document.write( "You can check these solutions in the 2nd equation \n" ); document.write( "
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