document.write( "Question 13878: the perimeter of a rectangle is 122m. the length of the rectangle is 11m less five times the width. find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #7008 by kunal_122(19)\"\" \"About 
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\n" ); document.write( "let x be the width\r
\n" ); document.write( "\n" ); document.write( "and 5x-11 the length\r
\n" ); document.write( "\n" ); document.write( "so the equation is:\r
\n" ); document.write( "\n" ); document.write( "5x-11+x+5x-11+x=122
\n" ); document.write( "12x-22=122
\n" ); document.write( "12x=144
\n" ); document.write( "x=12\r
\n" ); document.write( "\n" ); document.write( "so width is 12 and so lenght is 5*12-11=49\r
\n" ); document.write( "\n" ); document.write( "and now u can check 49+12+49+12=122\r
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