document.write( "Question 1086552: A chemical store room has a 90% acid solution and 40% solution. How many CENTILITERS of the 90% solution should be added to 50 CENTILITERS of the 40% solution to yield up a 50% solution? \r
\n" ); document.write( "\n" ); document.write( "p.s. i caps the centiliters for clearer comprehension. Thank you sir/maam tutors! :)
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Algebra.Com's Answer #700779 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let x = amount of the 90% acid solution (in centiliters)\r
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\n" ); document.write( "\n" ); document.write( "We have 50 centiliters of the 40% solution.
\n" ); document.write( "This means we have 0.4*50 = 20 centiliters of pure acid\r
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\n" ); document.write( "\n" ); document.write( "We're adding on x more centiliters of the 90% solution.
\n" ); document.write( "There are an additional 0.9*x centiliters of pure acid. \r
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\n" ); document.write( "\n" ); document.write( "In total, we have 0.9*x+20 centiliters of pure acid.\r
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\n" ); document.write( "\n" ); document.write( "This is out of x+50 centiliters of solution. \r
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\n" ); document.write( "\n" ); document.write( "Divide the expressions 0.9*x + 20 over x+50 to get \"%280.9%2Ax+%2B+20%29%2F%28x%2B50%29\".
\n" ); document.write( "This fraction represents the ratio of pure acid to total solution.
\n" ); document.write( "We want this ratio to be equal to 50%.
\n" ); document.write( "This is because we want the final solution to be 50% acid\r
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\n" ); document.write( "\n" ); document.write( "So set \"%280.9%2Ax+%2B+20%29%2F%28x%2B50%29\" equal to 0.50 to get \"%280.9%2Ax+%2B+20%29%2F%28x%2B50%29+=+0.50\"\r
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\n" ); document.write( "\n" ); document.write( "Now solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"%280.9%2Ax+%2B+20%29%2F%28x%2B50%29+=+0.50\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.9x+%2B+20+=+0.50%28x%2B50%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.9x+%2B+20+=+0.50%28x%29%2B0.50%2A%2850%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.9x+%2B+20+=+0.50x%2B25\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.9x+%2B+20-0.50x+=+0.50x%2B25-0.50x\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.4x+%2B+20+=+25\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.4x+%2B+20-20+=+25-20\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.4x+=+5\"\r
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\n" ); document.write( "\n" ); document.write( "\"%280.4x%29%2F%280.4%29+=+%285%29%2F%280.4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+12.5\"\r
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\n" ); document.write( "\n" ); document.write( "We need 12.5 (12 and a half) centiliters of the 90% solution.
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